For example:

 
Void func (int) {
STD: : cout & lt; <"In func"; 
} 

Void test (void func (*) (int)) {
Func (1); 
} 

Int main () {
The test ([] (int a) {STD: : cout & lt; <"Lambda" & lt; } 

How to set up the parameter, make the test () function accepts the lambda function, more than a & amp; , can introduce external variables:

 
Int main () {
Int b=9; 
The test ([& amp;] {(int a) STD: : cout & lt; <"Lambda" & lt; } 

CodePudding user response:

It is your turn to a lambda expressions to a function pointer, rule is allowed, but the transformation of the lambda there cannot be caught

CodePudding user response:

 # include & lt; Iostream> 
using namespace std; 
Void funcx (int) {
STD: : cout & lt; <"Func" In & lt; } 

Template 
Void test func (F) {
Func (1); 
} 

Int main () {
Int b=10; 
The test (funcx); 
The test ([& amp;] {(int a) STD: : cout & lt; <"Lambda" & lt; }