Small white consult how pointer to two-dimensional array, there are problems in this code, after poi-CodePudding

# include "stdio.h"
# include "string. H"
Int main ()
{
Char s [5] [100].
Char * p;
* p=s;
Int I, k, len, minlen;
for(i=0; i<5; I++)
Gets (p + I);
Minlen=strlen (p + 0);
Printf (" % d ", minlen);
for(i=1; i<5; I++)
{
Len=strlen (p + I);
If (len{
Minlen=len;
k=i;
}
}
Puts (p + k);
}

CodePudding user response:

What is a pointer variable
How is for pointer assignment
How is the goal of to the pointer assignment
This writing error is a pointer to pointer without a goal before target assignment

CodePudding user response:

Modified as follows, for your reference:

 # include "stdio.h" 
# include "string. H" 
Int main (int arg c, char * argv []) 
{
Char s [5] [100]. 
Char (* p) [100];//char * p 

P=s;//* p=s; 

Int I, k=0, len, minlen;//int I, k, len, minlen; 

for(i=0; i<5; I++) 
Gets (* (p + I));//gets (p + I); 

Minlen=strlen (* (p + 0));//minlen=strlen (p + 0); 
Printf (" % d \ n ", minlen);//printf (" % d ", minlen); 

for(i=1; i<5; I++) 
{
Len=strlen (* (p + I));//len=strlen (p + I); 
If (len{
Minlen=len; 
k=i; 
} 
} 
Puts (* (p + k));//puts (p + k); 

return 0; 
}

CodePudding user response:

reference 1st floor forever74 response:

what is a pointer variableHow is for pointer assignment
How is the goal of to the pointer assignment
This writing error is a pointer to pointer without a goal before target assignment

Should be p=a, but the output of the answer, the printf (" % d ", minlen) do you have any questions just to test the calculation length of the string, the input string aa, his output is 11

CodePudding user response:

refer to the second floor QZJHJXJ response:

modify as follows, for reference:

 # include "stdio.h" 
# include "string. H" 
Int main (int arg c, char * argv []) 
{
Char s [5] [100]. 
Char (* p) [100];//char * p 

P=s;//* p=s; 

Int I, k=0, len, minlen;//int I, k, len, minlen; 

for(i=0; i<5; I++) 
Gets (* (p + I));//gets (p + I); 

Minlen=strlen (* (p + 0));//minlen=strlen (p + 0); 
Printf (" % d \ n ", minlen);//printf (" % d ", minlen); 

for(i=1; i<5; I++) 
{
Len=strlen (* (p + I));//len=strlen (p + I); 
If (len{
Minlen=len; 
k=i; 
} 
} 
Puts (* (p + k));//puts (p + k); 

return 0; 
}

Ask: I don't understand the meaning of (* p) [100], haven't learned, and he gave the front code, can use char * p can't into a char (* p) [100]

CodePudding user response:

line array pointer definition method is as follows:
Data types (* pointer variable name) the number of columns] [two-dimensional array;
For example, line array pointer are defined as follows: int (* p) [100]. It says there are about 100 a char type p points to the element of a one-dimensional array, namely the p for the row pointer, at this point, can be used as follows to the pointer p assignment: p=s;

reference 4 floor m0_52291497 response:

Quote: refer to the second floor QZJHJXJ response:

modify as follows, for reference:

 # include "stdio.h" 
# include "string. H" 
Int main (int arg c, char * argv []) 
{
Char s [5] [100]. 
Char (* p) [100];//char * p 

P=s;//* p=s; 

Int I, k=0, len, minlen;//int I, k, len, minlen; 

for(i=0; i<5; I++) 
Gets (* (p + I));//gets (p + I); 

Minlen=strlen (* (p + 0));//minlen=strlen (p + 0); 
Printf (" % d \ n ", minlen);//printf (" % d ", minlen); 

for(i=1; i<5; I++) 
{
Len=strlen (* (p + I));//len=strlen (p + I); 
If (len{
Minlen=len; 
k=i; 
} 
} 
Puts (* (p + k));//puts (p + k); 

return 0; 
}

Ask: I don't understand the meaning of (* p) [100], haven't learned, and he gave the front code, can use char * p can't into a char (* p) [100]

modify as follows:

 # include "stdio.h" 
# include "string. H" 
Int main (int arg c, char * argv []) 
{
Char s [5] [100]. 
Char * p;//(* p) [100]; 

P=s [0];//* p=s; 

Int I, k=0, len, minlen;//int I, k, len, minlen; 

for(i=0; i<5; I++) 
Gets (p + I * 100);//gets (p + I); 

Minlen=strlen (p + 0); 
Printf (" % d \ n ", minlen);//printf (" % d ", minlen); 

for(i=1; i<5; I++) 
{
Len=strlen (p + I * 100);//len=strlen (p + I); 
If (len{
Minlen=len; 
k=i; 
} 
} 
Puts (p + k * 100);//puts (p + k); 

return 0; 
}

CodePudding user response:

reference 5 floor QZJHJXJ reply:

line array pointer definition method is as follows:
Data types (* pointer variable name) the number of columns] [two-dimensional array;
For example, line array pointer are defined as follows: int (* p) [100]. It says there are about 100 a char type p points to the element of a one-dimensional array, namely the p for the row pointer, at this point, can be used as follows to the pointer p assignment: p=s;

Quote: refer to 4th floor m0_52291497 response:

Quote: refer to the second floor QZJHJXJ response:
modify as follows, for reference:
# include "stdio.h"
# include "string. H"
Int main (int arg c, char * argv [])
{
Char s [5] [100].
Char (* p) [100];//char * p

P=s;//* p=s;

Int I, k=0, len, minlen;//int I, k, len, minlen;

for(i=0; i<5; I++)
Gets (* (p + I));//gets (p + I);

Minlen=strlen (* (p + 0));//minlen=strlen (p + 0);
Printf (" % d \ n ", minlen); nullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnullnull