First why not consult the

CodePudding user response:

 # include & lt; stdio.h> 

Void show_digit (num); 

Int main (void) 
{

Long n; 

The scanf (" % ld ", & amp; N); 

Show_digit (n); 

return 0; 
} 

Void show_digit (num) 
{
If (num==0) 
return; 

Show_digit (num/10); 
Printf (" % ld, "num % 10); 
} 

For your reference ~

CodePudding user response:

Modified as follows, for your reference:

 # include 
Int main (int arg c, char * argv []) 
{
Long n, j, a, b;//I, 
The scanf (" % d ", & amp; N); 
If (n==0) printf (" % d ", n); 
A=b=n; 
J=1; 
While (b> 9) {
B=b/10; 
J *=10; 
} 
for(; J> 0; J/=10) {
B=a/j; 
A=n % j; 
Printf (" % d ", b); 
} 

return 0; 
} 

CodePudding user response:

Write too wordy simple point directly to the point:

CodePudding user response:

The building Lord at the end of your code if there are any nonzero but with zero input will be very embarrassed,