I small white one, just to learn something, try to weave a little game to play, the result is out of the question here, for the great god solve meowed

 
#include  
#include  
using namespace std; 
Int menuForMethod (pet playerPet);//the menu function that returns a value 
Int main () {... }
Int menuForMethod (pet playerPet) 
{
int num; 
Cout & lt; Cout & lt; <"* * * * * * * * * * * * menu options * * * * * * * * * * * *" & lt; Cout & lt; Cout & lt; <"1) open the store system" & lt; Cout & lt; <"2) forward to adventure!" Cout & lt; <"3) to examine their pet" & lt; Cout & lt; Cout & lt; <"* * * * * * * * * * * * menu options * * * * * * * * * * * *" & lt; Cout & lt; Cout & lt; <"Choice:" & lt; Cin & gt;> Num. 
While (cin) fail () | | (num!=1 & amp; & Num!=2 & amp; & Num!=3)) {//inspection input 
Cin. The clear (); 
Cin. Ignore (); 
Cout & lt; <"Input error, please input again" & lt; Cin & gt;> Num. 
}
If (num==1 | | num==2) {
return num; 
} else {
Prt_playerPet (playerPet); 
//it is no good added return here 
}
//it is no good added return here 
}

Is this menuForMethod function, the compiler is always an error, says menuForMethod () needs to return values, can function return is there, and I add you can return the place is added, it is no use,
The great god solution, urgent!!

CodePudding user response:

The menu function to the void, not int,