CodePudding user response:

+ + s + b++ % b + + a + + + - *
1 + - 4% - 3 * 3 + 1
First calculate s + 1 offspring into use before the original value - 4 a performed b++, plus one offspring into computing a + 1 offspring into use the original value of 1

To calculate x + + x expression before using, x++ is to use the original value of the x again after calculation