# include "stdio.h"
The main ()
{
Int k, j, s;
For (k=2; K<6; K++ k++);
{s=1;
For (j=k; J<6; J++) s=s + j;
}
Printf (" s=% d, k=% d ", s, k);
}

CodePudding user response:

Because of the for () followed by a semicolon "; ',

CodePudding user response:

Pick up points for reference:

 # include" stdio.h "
The main () 
{
Int k, j, s; 
S=1;//setting a 
For (k=2; K<6; K +=2)//for (k=2; K<6; K++ k++) two k++ equivalent to k=k + 2//; Many a semicolon 
{
//s=1; The K cycle in every time buy 1 
For (j=k; J<6; J++) 
S=s + j; 
} 
Printf (" s=% d, k=% d ", s, k); 

return 0; 
} 

CodePudding user response:

Follow up step by step:

 
# include "stdio.h" 
The main () 
{
Int k, j, s; 
For (k=2; K<6; K++ k++); 
//the behind for a; So after perform the cycle, k=6 
//may is meant the following this paragraph is the loop body, but as a result of what is said above for a semicolon at the end of the line, so what's happening with you think the difference is very big 
{
S=1; 
For (j=k; J<6; J++) s=s + j;//as a result of k=6, the circulation j<6, in the loop body is executed to 
//this time there is no change in the value of s, still 1 
} 
Printf (" s=% d, k=% d ", s, k); 
} 

CodePudding user response:

Thank you