C language output, the output noise, more help!!!!!-CodePudding

 
# include 
Void the alter (char [] a) 
{
int i; 
For (I=3; I>=0; I -) 
{
A (2 * I + 1)=a, [I]. 
A (2 * I]=' '; 
} 
Puts (a); 

} 
Int main () 
{
Char a, [40]. 
Printf (" input a four-digit: \ n "); 
The scanf (" % s ", & amp; A); 
The alter (a); 
return 0; 
}

Why do many output something behind?

CodePudding user response:

You don't handle end, just one more,
For (I=4; I>=0; I -)

CodePudding user response:

A less '\ 0'

CodePudding user response:

No terminator has been print down until the end, the following is a way to modify the code, reference,

 
# include 
Void the alter (char [] a) 
{
int i; 
For (I=3; I>=0; I -) 
{
A (2 * I + 1)=a, [I]. 
A (2 * I]=' '; 
} 
A (2 * 4]='\ 0';//in the final end of add a 
Puts (a); 

} 
Int main () 
{
Char a, [40]. 
Printf (" input a four-digit: \ n "); 
The scanf (" % s ", & amp; A); 
The alter (a); 
return 0; 
}

CodePudding user response:

reference 1st floor forever74 response:

you don't have the handle end, more than one line,
For (I=4; I>=0; I -)

Thank you thank you very much

CodePudding user response:

reference room reply: 3/f the cloud

no terminator has been print down until the end, the following is a way to modify the code, reference,

 
# include 
Void the alter (char [] a) 
{
int i; 
For (I=3; I>=0; I -) 
{
A (2 * I + 1)=a, [I]. 
A (2 * I]=' '; 
} 
A (2 * 4]='\ 0';//in the final end of add a 
Puts (a); 

} 
Int main () 
{
Char a, [40]. 
Printf (" input a four-digit: \ n "); 
The scanf (" % s ", & amp; A); 
The alter (a); 
return 0; 
}

OK I understand you thank you thank you