This question is similar to "Are all pointers guaranteed to round-trip through void * correctly?" but slightly deeper.

Given:

#include <stdint.h>

int i;
int *ip1 = &i;
void *vp1 = ip1;
intptr_t x = (intptr_t)vp1;
void *vp2 = (void *)x;
int *ip2 = vp2;

then vp1 == vp2 is guaranteed to be true (even though they might not share the same binary representation), but is ip1 == ip2 guaranteed to be true? I.e., is the equality relation transitive in this case?

CodePudding user response：

This conversion is guaranteed to work.

First, conversion from an object pointer to a void * and back is described in section 6.3.2.3p1 of the C standard:

A pointer to void may be converted to or from a pointer to any object type. A pointer to any object type may be converted to a pointer to void and back again; the result shall compare equal to the original pointer

Second, conversion from a void * to a intptr_t and back is described in section 7.20.1.4p1:

The following type designates a signed integer type with the property that any valid pointer to void can be converted to this type, then converted back to pointer to void, and the result will compare equal to the original pointer:

intptr_t

The following type designates an unsigned integer type with the property that any valid pointer to void can be converted to this type, then converted back to pointer to void, and the result will compare equal to the original pointer:

uintptr_t

These types are optional.

In this case, an int * (ip1) is converted to a void * (vp1), and the void * to a intptr_t.

The intptr_t is converted back to a void * (vp2). By 7.20.1.4p1, vp2 must compare equal to vp1.

Then vp2 is converted to an int * (ip2). Since vp2 is the same as vp1, the conversion of vp2 to int * is equivalent to converting the vp1 to int * and therefore will result in a pointer that will compare equal to ip1 as per 6.3.2.3p1.

CodePudding user response：

Transitivity of equality for pointers, regardless of provenance, follows from the specification of the equality operators. C 2018 6.5.9 6 says:

Two pointers compare equal if and only if both are null pointers, both are pointers to the same object (including a pointer to an object and a subobject at its beginning) or function, both are pointers to one past the last element of the same array object, or one is a pointer to one past the end of one array object and the other is a pointer to the start of a different array object that happens to immediately follow the first array object in the address space.

Dismissing null pointers and pointers to functions, which are not an issue here, given that a == b and b == c evaluate as true, they must satisfy one of the conditions listed in the specification, so we have these cases:

Note there are no cases where b points to an object in the first column and to one past the last element of an array in the second column or vice-versa: Whichever of these two kinds of pointer it is, it must be the same kind in a == b and b == c.