Pass whole incoming data to curl - Laravel-CodePudding

I wanted to pass the whole incoming data (that is, $request) to the curl not wanted to post to a particular field in the endpoint as subjectId=>1 as am running this curl request for different endPoint everytime. The below curl request will work if CURLOPT_URL => $url . $subjectId, was given. As my input changes for every end point, i've to pass everything that comes in the input to the curl , i can't pass it as an arary $subjectId. Is there any way to do this?

Currently, dd($Response); returns null

Am giving a postman input like this:

{
   "subjectId":"1"
}

Curl

public function getContentqApiPost(Request $request) 
    {
        $token = "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.ey";
        $headers = [
            "Accept: application/json",
            "Authorization: Bearer " . $token
        ];
       
          $url="http://127.0.0.1:9000/api/courses/course-per-subject";
        $subjectId = "?subjectId=$request->subjectId";
        $ch = curl_init();
        $curlConfig = array(
         //   CURLOPT_URL            => $url . $subjectId,
         CURLOPT_URL            => $url . $request,
            
            CURLOPT_CUSTOMREQUEST => "GET",
            CURLOPT_RETURNTRANSFER => true,
            
            CURLOPT_HTTPHEADER => $headers, 
        );
         
        curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
        curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
        curl_setopt_array($ch, $curlConfig);
        
        $result = trim(curl_exec($ch));
       
        $Response = json_decode($result, true);
        
        if (curl_errno($ch)) {
            $error_msg = curl_error($ch);
            echo $error_msg;
        }

        curl_close($ch);

        return $Response;
    }

CodePudding user response：

If you would like to pass all params of $request to curl:

$queryParams  = '';
$delimeter = '?';
foreach($request->all() as $k => $v){
    $queryParams .= "$delimeter$k=$v";
    $delimeter = '&';
}

Also You can only pass the params you want:

foreach($request->only(['subjectId']) as $k => $v){
    // code here
}

Finally you have:

CURLOPT_URL            => $url . $queryParams,

CodePudding user response：

Answer

Assuming you want to pass the entire GET query string as-is:

$query_string = str_replace($request->url(), "", $request->fullUrl());
$url = "http://localhost:9000/api/courses/course-per-subject" . $query_string;

This works because $request->url() returns the URL without the query string parameters, while $request->fullUrl() returns the URL with all the query string parameters, so we can use str_replace with an empty replacement to remove the non-query part. Note that $query_string will already start with a ? so there is no need to add that yourself.

Other suggestions

Unless your Laravel API is a 1:1 copy of the backend API, I strongly suggest writing a class that interfaces with the backend API, then provide it to your Laravel controllers using dependency injection. E.g.

class CourseCatalogApi {
   public function getSubjectsInCourse(String $course){
       ... // your curl code here
   }
}

Finally, since you are already using Laravel, there is no need to write such low level code using curl to make HTTP requests. Consider using guzzlehttp, which is already a dependency of Laravel.