I want to iterate serial numbers from 000 to 999 in Python and save them to a txt file

import os
os.system ('clear')

lis9 = 01000
while lis9 < 01099 :
   lis9 = lis9 1
   print (lis9)

How do I start from a specific number and end at a specific number? The numbers start from zero

Each number begins on a new line

For example

01000
01001
.
01010
.
.
01099

CodePudding user response：

Use f string

with open('out.txt','w') as f:
    for n in range(0,1000):
        f.write(f'{n:03}\n')

output ('out.txt')

000
001
002
003
...
996
997
998
999

CodePudding user response：

I like one liners for this kind of thing myself:

print([str(x)[-3:] for x in range(1000,2000)], sep="\n", file=open("out.txt","w"))

CodePudding user response：

The function range() can serve your goal: https://docs.python.org/3/library/functions.html#func-range

You can use it by range(1000) and then going through it by:

for i in range(1000):
    print(i)

And it would print line by line from 0 to 999. If you want the number to be 000 and not 0, (086 instead of 86 etc) you can use print(f"{i:0>3}")

CodePudding user response：

with open("file.txt", "w") as f:
    f.writelines("\n".join([f"{x:03}" for x in range(1000)]))