Printing something on the basis of a condition in a column of a df-CodePudding

I have a df as below and need to print a string on the basis of the condition as follows:

       Name Age     University  City
0      Ankit    23          BHU     Pune
1     Aishwarya 21          BHU     Pune
2     Shaurya   22          BHU     Pune
3     Shivangi  21          BHU     Pune

for i in df:
    if df['Age']=='BHU'and df['City']=='Pune':
        print('correct')
    else:
        print('error')

gives ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

CodePudding user response：

You can looping by array created in numpy.where:

arr = np.where((df['Age']=='BHU') & (df['City']=='Pune'), 'correct', 'error')

for val in arr:
     print(val)

Your solution is possible use:

for row in df.itertuples():
    if (row['Age']=='BHU') and (row['City']=='Pune'):
        print('correct')
    else:
        print('error')

CodePudding user response：

I think you are comparing University and City name. If University is "BHU" and city is "Pune" then you want to print("correct") otherwise you want to print error. If my thought is right then you should follow this code below.

for i in range(0,len(df)):
    if df.loc[i, "University"] == "BHU" and df.loc[i, "City"] == "Pune":
        print("correct")
    else:
        print("error")