I am a novice coder. Trying my hand at creating an instagram bot and I'm following the instructions found here: (https://realpython.com/instagram-bot-python-instapy/)
I can fill in the elements for user name and password, but I'm having trouble clicking the login link. Using the -
#submit = browser.find_element_by_tag_name('form')
#submit.submit()
- portion of my code works to log in, but I would like to be able to use find element by xpath and for this so I can apply it in different situations. If someone could please let me know where I can look in the HTML on the instagram page to find what I'm looking for, or direct me towards any helpful reading, I'd really appreciate it! I've tried a few ways to do this.
Here is my code. I also added photos of my code and error message.
from time import sleep
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
#sets browser to firefox - need to make sure that geckodriver and firefox are in the path
browser = webdriver.Firefox()
#opens firefox to instagram#
browser.get('https://www.instagram.com/accounts/login/?source=auth_switcher')
#tells selenium to wait 5 seconds before trying again if it can't find something
browser.implicitly_wait(10)
print ('i waited')
user = 'username'
password = 'password'
##### USERNAME #####
username = browser.find_element_by_xpath("//input[@name='username']")
username.send_keys(user)
#username = browser.find_element_by_name('username')
#username.send_keys(user)
##### PASSWORD #####
password = browser.find_element_by_xpath("//input[@name='password']")
password.send_keys(password)
#password = browser.find_element_by_name('password')
#password.send_keys(password)
browser.implicitly_wait(10)
##### LOG IN #####
#instead of searching for the Button (Log In) you can simply press enter when you already selected the password or the username input element.
#submit = browser.find_element_by_tag_name('form')
#submit.submit()
#login_link = browser.find_element_by_xpath("//article/div/div/p/a[text()='Log in']")
login_link = browser.find_element_by_xpath("//a[text()='Log in']")
login_link.click()
#login_form = browser.find_element_by_xpath("//form[@id='loginForm']")
#form.submit()
print ('login incomplete :)')
sleep(5)
browser.quit() #quits geckodriver and mozilla
print ('closed')
CodePudding user response：
Your xpath is bit wrong. you are using
//a[text()='Log in']
but Log in is inside div tag, not a tag.
Please use this xpath
//div[text()='Log In']/..
In your code
login_link = browser.find_element_by_xpath("//div[text()='Log In']/..")
login_link.click()
The HTML is
<div class=" qF0y9 Igw0E IwRSH eGOV_ _4EzTm ">Log In</div>
and we are using text() to target text Log in and then we are looking for button using /.. which is a parent node.
CodePudding user response：
Replace this link
login_link = browser.find_element_by_xpath("//a[text()='Log in']")
with
login_link = browser.find_element_by_xpath("//div[contains(text(),'Log In')]")
And you should be good. Since the Login In button is wrapped inside a div element and not a element.
CodePudding user response：
As already explained Log In is in a div tag under a button tag with type submit. You can use this xpath too.
browser.find_element_by_xpath("//button[@type='submit']").click()