i want to call this 3d array-CodePudding

how can i this function this is an 3D array i want to scan from user the number of row ,colum,cell then send 3D array


   #include <stdio.h>

    void School (int(*ptr)[int col][int cell] );//this is a user function 

    void main (void){
    int row ;//number of row 
    int col ;//number of colum
    int cell ;//number of cell
    
    printf("Enter Number OF School Layers \n");
    scanf("%d",&row);
    printf("Enter Number OF Classes in each Layer \n");
    scanf("%d",&col);
    printf("Enter Number OF Students in each Class \n");
    scanf("%d",&cell);
    

    
    int arr [row][col][cell];
    
    

    School(arr,row,col,cell);//calling of function 

    }
    void School (int(*ptr)[int col][int cell] ){//i want what write here
    
    }

in this code i have problem

CodePudding user response：

void School (size_t layers, size_t col, size_t cell, int (*ptr)[col][cell])
{
        
}

CodePudding user response：

First you need to update the function prototype to accept dimensions before the array parameter (pointer to array actually).

void School (int rows, int cols, int cells, int arr[rows][cols][cells]);

Then invoke it as:

School(row, col, cell, arr);

The actual scanning code would be:

void School (int rows, int cols, int cells, int arr[rows][cols][cells]) {
for (int row = 0; row < rows;   row)
for (int col = 0; col < cols;   col)
for (int cell = 0; cell < cells;   cell)
   scanf("%d", &arr[row][col][cell]);
}

GCC has extensions that allows to declare the parameters, before passing it.

void School (int rows, cols, cells; int arr[rows][cols][cells], int rows, int cols, int cells);

This would let you call the function as:

School(arr, row, col, cell);