Question related to Functions, multiple arguments and lists [closed]-CodePudding

I need to write a function that takes a number as a parameter and a list, checks each element in the list to locate where the number exists and returns the index.

For example:

func(1, [11, 14, 56, 71, 9])

I want the answer: "The number is located at: [0, 1, 3]"

If the number doesn't exist in the list, then just print a blank list []

CodePudding user response：

Since you're trying to figure out if the input number is a digit in any of the list numbers, the easiest thing is to convert both to strings and use the in operator:

>>> def func(n, h):
...     return [i for i, x in enumerate(h) if str(n) in str(x)]
...
>>> print(f"The number is located at: {func(1, [11, 14, 56, 71, 9])}")
The number is located at: [0, 1, 3]

CodePudding user response：

def find(x,L:list):
    g = []
    for i in L :
        if str(x) in str(i):
            g.append(L.index(i))
    return g 

print(find(1, [11, 14, 56, 71, 9]))