Below is an example of a String that I want to split it to 3 parts from a substring

test01String001s

Examples:

• example_1 subString == "0"

  res: [ "test","0","1String001s" ] - test01String001s

• example_2 subString == "st"

  res: [ "te","st","01String001s" ] - test01String001s

• example_3 subString == "01s"

  res: [ "test01String0","01s", "" ] - test01String001s

• example_4 subString == "t"

  res: [ "","t","est01String001s", ] - test01String001s

I try to resolve it via

 var string='test01String001s'
 var keyword="01"
 console.log(string.split(keyword));

output:

     ["test","String0","s"]  instead of [ "test","01","String001s"]

or

 var string='test01String001s'
 var keyword="0"
 console.log(string .split(keyword, 2));

output

 ["test","1String"]

CodePudding user response：

To get 3 parts I wouldn't use split, but use some logic

const mystring = 'test01String001s'
const sp = ['01','1','t','st', '1s']

sp.forEach(item=>{
  let idx=mystring.indexOf(item)
  let result=[]
  if(idx===0){
    result.push('')
    result.push(item)
    result.push(mystring.slice(item.length))
  }else if (idx item.length ==mystring.length){
    result.push(mystring.slice(0,idx))
    result.push(item)
    result.push('')
  }else if(idx!=-1){
    result.push(mystring.slice(0,idx))
    result.push(item)
    result.push(mystring.slice(idx item.length))
  }
  console.log(result)
})

CodePudding user response：

Try this.

var string = "test01String001s";
var splitKey = '01';
var components = string.split(splitKey);
var array = ([components.shift(), components.join(splitKey)]);
array.splice(1, 0, splitKey);
console.log(array.join());

Output: test,01,String001s

CodePudding user response：

This should work:

const test = 'test01String001s';
const key = "t";
const re = new RegExp('(.*?)('   key   ')(.*)');
const result = test.match(re, "regex");
result.shift();

console.log(result);

So this regex match is returning an array of:

(.*?) - anything before key

(' key ') - key

(.*) - anything after key

Unfortunately it also returns the whole matched word, so I used shift to remove first match from array.

CodePudding user response：

I have written one function named split. It will work fine if splitter is found in a string, otherwise it will return [string, splitter, string]

For example:

string = 'test01String001s and splitter=01 now give output ["test", "0", "1String001s"]

if splitter = "apple" it will return ["test01String001s", "apple", "test01String001s"]

If you want to return empty value when splitter not found in a string, simply add if(splitter_index < 0) return ["", "", ""] before current return statement line in split function.

Please check all examples below and anyone think any changes needed please comment down.

let string = "test01String001s"

function split(string, splitter) {
    let splitter_index = string.indexOf(splitter);
    
    return [string.slice(0, splitter_index), splitter, string.slice(splitter_index splitter.length)];
}

// example_1
console.log(split(string, '0'));

// example_2
console.log(split(string, 'st'));

// example_3
console.log(split(string, '01s'));

// example_4
console.log(split(string, 't'));