How to get the total number of lines in an output-CodePudding

I have a relatively simple question. I made this code that basically calculates all the different combinations to make a dollar using pennies, nickels, quarters and dollar coins. The code works fine,its just that I need it to also tell me the total number of possibilities it printed, at the end of the code. I would appreciate some help :)

def alter(s, coins_free, coins_in_use):
  if sum(coins_in_use) == s:
    yield coins_in_use
  elif sum(coins_in_use) > s:
    pass
  elif coins_free == []:
    pass
  else:
    for c in alter(n, coins_free[:], coins_in_use [coins_free[0]]):
      yield c
    for c in alter(n, coins_free [1:], coins_in_use):
        yield c
n = 100
coins = [1, 5, 10, 25, 100]

soloution = [s for s in alter(n, coins, [])]
for s in soloution:
  print(s)

CodePudding user response：

You just to add print(f'Total no of possibilities: {len(soloution)}') line at the end of your code like following.

Printing Code:

soloution = [s for s in alter(n, coins, [])]
for s in soloution:
  print(s)

print(f'Total no of possibilities: {len(soloution)}')

Output:

Total no of possibilities: 243

CodePudding user response：

You might not actually need to make a list. In that case, you could use enumerate(start=1):

possibilities = alter(n, coins, [])
for i, p in enumerate(possibilities, 1):
    print(p)
print('Total number of possibilities:', i)

Although, FWIW, if you do need to make a list, the comprehension is kind of redundant and this is cleaner:

soloution = list(alter(n, coins, []))