How to represent java float as a binary literal?-CodePudding

I try to figure out how float and doubles work in Java. there is explained that we can represent 5.3 as

0 | 10000001 | 01010011001100110011001

But when I try to write it as a binary java literal

float number = 0b01000000101010011001100110011001;
System.out.println(number);

i get the output 1.0848567E9.

If I use the way to represent 5.3 as binary from this question

int intBits = Float.floatToIntBits(5.3F);
String binary = Integer.toBinaryString(intBits);
System.out.println(binary);

i get a completely confusing result 1000000101010011001100110011010 with 1 in the first position, which as I thought means a negative sign.

May somebody help me to understand what I do wrong? Can I use binary java literals to represent floats and doubles?

Thanks.

CodePudding user response：

According to the Java Language Specification, there is no binary float literal of the form you want.

0b01000000101010011001100110011001 is an int literal, but there is a method to convert this int to a float:

System.out.println(Float.intBitsToFloat(0b01000000101010011001100110011001));

This prints 5.2999997, because your representation isn't the most accurate. A more accurate one is:

0b01000000101010011001100110011010

Using this would print 5.3.

See also the tool IEEE Floating Point Converter, which you can use to get the binary representations of floats.