Get a file path from the explorer menu to a Powershell variable-CodePudding

I need to make a API call where file upload operation is required how can I prompt user to select the file from explorer and use the path after storing in a variable. I found similar question but it only works for folder.

CodePudding user response：

On Windows, you can take advantage the OpenFileDialog Windows Forms component:

function Select-File {
  param([string]$Directory = $PWD)

  $dialog = [System.Windows.Forms.OpenFileDialog]::new()

  $dialog.InitialDirectory = (Resolve-Path $Directory).Path
  $dialog.RestoreDirectory = $true

  $result = $dialog.ShowDialog()

  if($result -eq [System.Windows.Forms.DialogResult]::OK){
    return $dialog.FileName
  }
}

Then use like so:

$path = Select-File
if(Test-Path $path){
  Upload-File -Path $path
}