How can I build a shell script to build a Docker-Compose Image and start up the Docker container if-CodePudding

I'm trying to write a shell script that will attempt to build a Docker-Compose image, then if that's successful, start up the Docker container with it by doing a Docker-Compose up -d. In the second step, I load some JSON files into Mongo, but then if there's a problem with that step, I want want to stop all Docker services and print out an error message saying "Could not start Docker service because there was a problem seeding the DB."

My problem is that I don't know how to check if the image was created successfully in the first step. (I want to stop and print out a message saying that there were errors in the build.)

I think I can figure out something that checks if both services are running at the end, but I'm wondering if there is a way to print out the name of the problematic JSON file that couldn't load.

Does anyone have a similar script that I can use or modify for my own use?

CodePudding user response：

My understanding is you are trying to branch out the logic of the script based on whether the build command was a success. Here is what you can do:

cat create-image.sh

#!/bin/bash

docker build -q -t test-image .

if [ $? -eq 0 ]; then
   echo OK, images created
else
   echo FAIL, image not created
   exit 1
fi

echo "...DOING OTHER THINGS... (like docker-compose up)"

Let me know if this is what you were looking for.

CodePudding user response：

You don't need a script if you just want to build images before starting containers:

docker-compose --build up

If you must use a script, you can certain call the above command and check its exit code. There is no need to call docker build individually for every service in the docker-compose file.