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Find the city with highest number of amenities

Time:11-04

I am currently trying to crack a programming puzzle that has the very simple dataframe host with 2 columns named city and amenities (both are object datatype). Now, entries in both columns could be repeated multiple times. Below is the first few entries of host is beLOW

City    Amenities                                            Price($)
NYC    {TV,"Wireless Internet", "Air conditioning","Smoke      8
        detector",Essentials,"Lock on bedroom door"} 
LA     {"Wireless Internet",Kitchen,Washer,Dryer,"First aid    
        kit",Essentials,"Hair dryer","translation missing: 
         en.hosting_amenity_49","translation missing: 
         en.hosting_amenity_50"} 
                                                               10
SF     {TV,"Cable TV",Internet,"Wireless Internet",Kitchen,"Free 
        parking on premises","Pets live on this 
        property",Dog(s),"Indoor fireplace","Buzzer/wireless 
        intercom",Heating,Washer,Dryer,"Smoke detector","Carbon 
        monoxide detector","First aid kit","Safety card","Fire e 
        extinguisher",Essentials,Shampoo,"24-hour check- 
        in",Hangers,"Hair dryer",Iron,"Laptop friendly 
        workspace","translation missing: 
        en.hosting_amenity_49","translation missing: 
        en.hosting_amenity_50","Self Check-In",Lockbox}        15
NYC    {"Wireless Internet","Air 
        conditioning",Kitchen,Heating,"Suitable for events","Smoke 
        detector","Carbon monoxide detector","First aid kit","Fire 
        extinguisher",Essentials,Shampoo,"Lock on bedroom 
        door",Hangers,"translation missing: 
        en.hosting_amenity_49","translation missing: 
        en.hosting_amenity_50"}                                20
LA     {TV,Internet,"Wireless Internet","Air 
        conditioning",Kitchen,"Free parking on 
        premises",Essentials,Shampoo,"translation missing: 
        en.hosting_amenity_49","translation missing: 
        en.hosting_amenity_50"}
LA    {TV,"Cable TV",Internet,"Wireless Internet",Pool,Kitchen,"Free 
       parking on premises",Gym,Breakfast,"Hot tub","Indoor 
       fireplace",Heating,"Family/kid friendly",Washer,Dryer,"Smoke 
       detector","Carbon monoxide detector",Essentials,Shampoo,"Lock 
       on bedroom door",Hangers,"Private entrance"}           28

.....

Question. Output the city with the highest number of amenities.

My attempt. I tried using groupby() function to group it based on column city using host.groupby('city'). Now, I need to count successfully the number of elements in each set of Amenities. Since the data types are different, the len() function did not work because there are \ between each element in the set (for example, if I use host['amenities'][0], the output is "{TV,\"Wireless Internet\",\"Air conditioning\",\"Smoke detector\",\"Carbon monoxide detector\",Essentials,\"Lock on bedroom door\",Hangers,Iron}". Applying len() to this output would result in 134, which is clearly incorrect). I tried using host['amenities'][0].strip('\n') which removes the \, but the len() function still gives 134.

Can anyone please help me crack this problem?

To ddejohn's request:

Output of the host["Amenities"] = host["Amenities"].str.replace ...

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Output of the second line of your code

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Original dataset travel

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Output after travel.groupby('city') enter image description here

CodePudding user response:

Solution

import functools

# Process the Amenities strings into sets of strings
host["amenities"] = host["amenities"].str.replace('["{}]', "", regex=True).str.split(",").apply(set)

# Groupby city, perform the set union to remove duplicates, and get count of unique amenities
amenities_by_city = host.groupby("city")["amenities"].apply(lambda x: len(functools.reduce(set.union, x))).reset_index()

Output:

  city  amenities
0   LA         27
1  NYC         17
2   SF         29

Getting the city with the max number of amenities is achieved with

city_with_most_amenities = amenities_by_city.query("amenities == amenities.max()")

Output:

  city  amenities
2   SF         29
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