How to bring list of jenkins nodes to Active choice parameter and present only the current logged in-CodePudding

I have Jenkins job with active choice parameter with the name Computer. Which groovy script I should write to bring me all the Nodes names, and present only the one for the current logged in user? All nodes are with the label Desktop. I tried the below but it doesn't work:

import hudson.slaves.DumbSlave

def users = []
for (DumbSlave it : Hudson.instance.getSlaves()) {
  if(it.getLabelString().contains("Desktop")) {
    def currAgent = it?.computer?.name
    if(currAgent != null) {
      users.add(currAgent)
     }
  }
}

return users

Update: The suggestion answer present list of nodes, but Now I want to present only for the current logged in user. something like (it doesn't work for me):

import jenkins.model.*

def users = []
Jenkins.instance.nodes.each { node ->
    if(node.labelString.contains("Desktop")) {
        def currAgent = node?.computer?.name
        if(currAgent != null) {
            if(it.computer.systemProperties.containsKey('user.name')) {
                def user = it.computer.systemProperties['user.name'].toLowerCase()
                if(user != null) {
                    if(users.containsKey(user)) {
                        users.add(currAgent)
                    } 
                    else {
                        users[user] = [currAgent]
                    }
                }
            }
        }
    }
}

return users

CodePudding user response：

Try this:

import jenkins.model.*

def users = []
Jenkins.instance.nodes.each { node ->
    if(node.labelString.contains("Desktop")) {
        def currAgent = node?.computer?.name
        if(currAgent != null) {
            users.add(currAgent)
        }
    }
 }

 return users

Or make it Groovyer:

import jenkins.model.*

return Jenkins.instance.nodes.findAll { node ->
   node.labelString.contains("Desktop")}.collect { node ->
     node?.computer?.name }