Matplotlib overlay bimodal histograms-CodePudding

I am trying to put three "bimodal/binary histograms" on the same plot, labeled, and with the actual values instead of bins. Not sure if it makes sense... However, I would like to show the only 2 values that are present in each vector x1, x2 and x3.

Here is the code:

import matplotlib.pyplot as plt

x1 = [0.003996747444034554, 0.003996747444034554, 0.003996747458586469, 0.003996747444034554, 0.003996747444034554, 0.003996747444034554, 0.003996747458586469, 0.003996747444034554, 0.003996747444034554, 0.003996747444034554]
x2 = [0.003996536252088845, 0.003996536252088845, 0.003996536252088845, 0.003996536310296506, 0.003996536252088845, 0.003996536252088845, 0.003996536252088845, 0.003996536252088845, 0.003996536252088845, 0.003996536252088845]
x3 = [0.003996643703430891, 0.003996643703430891, 0.003996643703430891, 0.003996643703430891, 0.003996643703430891, 0.003996643761638552, 0.003996643703430891, 0.003996643703430891, 0.003996643703430891, 0.003996643703430891]

fig, axs = plt.subplots(1,3, figsize=([7,4]), sharey = True)
axs[0].hist(x1)
axs[1].hist(x2)
axs[2].hist(x3)
plt.tight_layout()

plt.figure(figsize=([7,4]))
plt.hist([x1,x2,x3])

Figure 1 is the plot of each histogram (x1, x2 and x3):

Figure 2 is the result of plotting all at once:

CodePudding user response：

The difference within each vector are much smaller than the differences between the vectors' means, therefore both histogram bars for each vector coincide.
For this particular case you could use a

(you'll need to zoom in to see the difference between the two x-positions of each vector)