Preg_Replace with preg_grep-CodePudding

i am trying to add code before and after inside the script tag with PHP

<script>
  hbspt.forms.create({
region: "na1",
portalId: "",
formId: ""
});
</script>

I am trying preg_grep with preg_replace to achieve it but i can not able to use multiple variable inside preg_replace and if i use array it is just output array.

$result = preg_grep("/hbspt\s*([\s\S]*?);/", $matches);
                $before = 'before';
                $after = 'after';
                $final = $before = $after;
                $regexes = '/hbspt\s*([\s\S]*?);/';
                
                
                return preg_replace( $regexes, "before $result after", $buffer );

where i am making mistake?

The result i want

<script>
before

  hbspt.forms.create({
region: "na1",
portalId: "",
formId: ""
});

after
</script>

CodePudding user response：

The easiest way to achieve what you want is:

$before = 'before';
$after  = 'after';
$source = '<script>
  hbspt.forms.create({
region: "na1",
portalId: "",
formId: ""
});
</script>';

echo "<script>\n$before\n" . 
     strip_tags($source) . 
     "\n$after\n</script>";

This results in:

<script>
before

  hbspt.forms.create({
region: "na1",
portalId: "",
formId: ""
});

after
</script>

See a PHP fiddle and strip_tags().

Alternatively, but slightly more complex, would be:

echo "<script>\n$before\n" . 
     substr($source, 8, -9) . 
     "\n$after\n</script>";

See: PHP Fiddle and substr().

The advantage is that it won't remove any tags inside your javascript.