how to print individual highest number in list that's inside another list python-CodePudding

i want to print highest number from my list (1231 here). i tried doing this here(posted below), but that doesn't work. it just shows the highest total number for each element in my list, which is, obviously, not what I want.

list = [ [1,3,251], [2], [1231,52,22] ]

for i in range(len(list)):
    for j in range(len(list[i])):
        print(max(list))

print:

[1231, 52, 22]
[1231, 52, 22]
[1231, 52, 22]
[1231, 52, 22]
[1231, 52, 22]
[1231, 52, 22]
[1231, 52, 22]

CodePudding user response：

Something like this:

xss = [ [1,3,251], [2], [1231,52,22] ]
result = max(max(xs) for xs in xss)
print(result)

CodePudding user response：

You are not using i and j anywhere in your code. Since you have a nested list you should have nested max calls:

>>> my_list = [[1, 3, 251], [2], [1231, 52, 22]]
>>> max(max(sub_list) for sub_list in my_list)
1231

Alternatively you can use a nested list comprehension to flatten the list, then make a single max call:

>>> max(i for sub_list in my_list for i in sub_list)
1231

CodePudding user response：

list = [ [1,3,251], [2], [1231,52,22] ]

for i in list:
    print(max(i))

You don't have to go through each list from the bigger list since you're using max.

CodePudding user response：

>>> list = [ [1,3,251], [2], [1231,52,22] ]
>>> max(max(list))
1231

It takes de max from the first list thant output the max from that list.