dict comprehension how do i get the value of a key divided by a value of the same key but in a diffe-CodePudding

I have 2 dictionaries
how can i get a dictionary that has the values divided buy the the value of the same key but in the other dictionary ?

stat_dict = {'good': 6537048, 'evil': 32000, 'neutral': 69467, 'nihilist': 81977, 'cool': 771180}

count_dict = {'good': 2, 'evil': 2, 'neutral': 2, 'nihilist': 2, 'cool': 2}

this what I am looking for an example for 'good'

avg_dict = {'good': 6537048/2}

i wrote this

avg_dict = {k:stat_dict[s_lst[2]]/count_dict[s_lst[2]] for k,v in stat_dict.items()}

but this gave

{'good': 385590.0, 'evil': 385590.0, 'neutral': 385590.0, 'nihilist': 385590.0, 'cool': 385590.0}

CodePudding user response：

Can't you just do:

for key in stat_dict.keys():
    avg_dict[key] = stat_dict[key]/count_dict[key]

Or are there keys in stat_dict that won't be in count_dict?

CodePudding user response：

What you're looking for is the Dict items method.

This will give you access to the key and value in your first dictionary:

{ key: value / count_dict[key] for (key, value) in stat_dict.items() }

See Python Dictionary Comprehension for more!

CodePudding user response：

You could simply use a dictionary comprehension:

{k:v/count_dict[k] for k,v in stat_dict.items()}

output:

{'good': 3268524.0,
 'evil': 16000.0,
 'neutral': 34733.5,
 'nihilist': 40988.5,
 'cool': 385590.0}

CodePudding user response：

Try:

avg_dict = {k:v/count_dict[k] for k,v in stat_dict.items()}