Convert list to string by using OOP-CodePudding

I'm trying to convert a list to one sequence string, by using a method in OOP. For example, I would like to convert ['Stack', 'over', 'flow', 3] to 'Stackoverflow3'.

When I tried doing that, the results were still returned as a list-

class NewClass:
    def __init__(self, array):
        self.array = array

    def __str__(self):
        return "".join(str(i) for i in self.array)


s_1 = ["Stack", "over", "flow", 3]
print(s_1.__str__())

I got this output - ['Stack', 'over', 'flow', 3]

Could you please guide me on how to do it right?

CodePudding user response：

You need to instantiate the class defined:

class NewClass:
    def __init__(self, array):
        self.array = array

    def __str__(self):
        return "".join(str(i) for i in self.array)


s_1 = NewClass(["Stack", "over", "flow", 3])
print(s_1)  # print 'automatically' uses __str__!

Out:

Stackoverflow3

CodePudding user response：

You need to create an instance of the class 'NewClass' before you pass the list argument. Your code should look like this: `

class NewClass:
    def __init__(self, array):
      self.array = array

    def __str__(self):
      return "".join(str(i) for i in self.array)


 s_1 = NewClass(["Stack", "over", "flow", 3])
 print(s_1.__str__())`