How do I add a decimal point between the first 9 digits and the last 2 digits?-CodePudding

How do I add a decimal point between the first 9 digits and the last 2 digits in the value that is being pulled in at line: $matchesLine[$key] = substr($line,166,11); ? As, the fetched values do not contain a decimal point.

Sample Data

Input: 00023659819

Desired output: #########.## >> 00236598.19

Script provided by @Shlomtzion

<?php


$text = "I0023540987805R01  ABC                         GHI                       OLirrt                 000000000000000100EA 0812160070451700   1098833   1990041300000001086000000000108600000000000996000000000032100000000000000000000000000000000000000000000000000000000000000000000006589000000000000000                                     P0012B    
0000002032902R01  DEF                         JKL                       KLijuI                 000000000000000100EA 0812160070451700   1029132   1997010800000002396000000000239600000120002326000000000000000000000000000000000000000000000000000000000000004560000000000000000000000000987600000000                                     A203SD   ";

echo '<pre>';
$txt = explode("\n",$text);

echo '<pre>';
print_r($txt);

foreach($txt as $key => $line){
    $subbedString = substr($line,2,11);

    $searchfor = '02354098780';
    //echo strpos($subbedString,$searchfor); 
    if(strpos($subbedString,$searchfor) === 0){
        $matches[$key] = $searchfor;
        $matchesLine[$key] = substr($line,166,11);
        echo "Found in line : $key";
    }

    
}

echo '<pre>';
print_r($matches);

echo '<pre>';
print_r($matchesLine);

CodePudding user response：

Here is one way to this via preg_replace:

$input = "00023659819";
$output = preg_replace("/(?=\d{2}$)/", ".", $input);
echo $output;  // 000236598.19

CodePudding user response：

If you already know that there are 11 digits, you can use substr_replace

$str = "00023659819";
echo substr_replace($str, ".", 9, 0);

Output

000236598.19

If you want to do the replacement when 11 digits, you can use preg_replace with 2 capture groups for 9 and 2 digits and in the replacement use the 2 capture groups with a dot in between $1.$2

$str = "00023659819";
echo preg_replace("/^(\d{9})(\d{2})$/", "$1.$2", $str);

Output

000236598.19