Rerurn filtered array which is not equal to another array list-CodePudding

I've a api with list of car.

const getAsset = async () => dbApi('list_cars', ['', 100])
     .then(result => result.map(e => e.symbol));

here, getAsset returns the car list.

0: "BMW"
1: "HONDA"
2: "SCODA"
3: "STAR"
4: "PETH"
5: "TEST"
6: "TESLA"

In the below code block, I tried to return list excluding BMW. And it worked well.

 const getAsset = async () => dbApi('list_cars', ['', 100])
     .then(result => result.filter(e => e.symbol != 'BMW' ).map(a => a.symbol));

Now, I want to go forward and return the list of car excluding BMW , HONDA and TEST.

const expect = ['BMW','HONDA','TEST'];

expected result :

0: "SCODA"
1: "STAR"
2: "PETH"
3: "TESLA"

What changes should I make in the above code block?

CodePudding user response：

You can do it by filter method, like this:

const cars = ["BMW","HONDA", "SCODA", "STAR", "PETH", "TEST", "TESLA"]
const except = ["BMW","HONDA","TEST"];

const filteredCars = cars.filter(car => !except.includes(car));
console.log(filteredCars)

CodePudding user response：

 const getAsset = async () => dbApi('list_cars', ['', 100])
     .then(result => result.filter(e => (e.symbol != 'BMW' && e.symbol != 'HONDA' && e.symbol != 'TEST') ).map(a => a.symbol));

CodePudding user response：

 const cars = ["BMW","HONDA", "SCODA", "STAR", "PETH", "TEST", "TESLA"];
 
 const filteredResult =  cars.filter(e => (e != 'BMW' && e != 'HONDA' && e != 'TEST'));

console.log(filteredResult);