How to alter the snippet below to fetch the first and second value in between the delimeters?

Output Example: First value: 9100450 and second value: HHkk based on the searchfor value: 12348888

$input = '0123456|BHKAHHHHkjkjkjkjk|12345678|JuiKKK121255
    9100450|HHkk|12348888|JuiKKK10000000021sdadad255';
$searchfor = '12348888';
$regexp = "/(?<=" . $searchfor . "\\|)\\w /m";
$result = preg_match_all($regexp, $input, $matches);
print_r($matches);

CodePudding user response：

You can use

$regexp = "/^([^|] )\|([^|] )\|" . $searchfor . "\|/m";

See the PHP demo and the regex demo. Details:

• ^ - (here, due to m) start of a line
• ([^|] ) - Group 1: any one or more chars other than a | char
• \| - a | char
• ([^|] ) - Group 2: any one or more chars other than a | char
• \| - a | char
• 12348888 - some hard-coded value
• \| - a | char.

If your $searchfor value can contain special chars, replace $searchfor with preg_quote($searchfor, '/') in the code.

See a PHP demo:

$input = '0123456|BHKAHHHHkjkjkjkjk|12345678|JuiKKK121255
9100450|HHkk|12348888|JuiKKK10000000021sdadad255';
$searchfor = '12348888';
$regexp = "/^([^|] )\|([^|] )\|" . $searchfor . "\|/m";
if (preg_match($regexp, $input, $match)) {
    $val1 = $match[1];
    $val2 = $match[2];
    echo "$val1\n$val2";
}