Raising TypeError when type is not correct-CodePudding

I'd like to call function foo(a, b, c), where arguments can be int or float Those arguments user inputs using space as a separator. For example: 1 8 9

In the same time user can input not only digits, bit make some typo like: 1 8k 9. In this case I should raise TypeError and type the number of incorrect element

a, b, c = map(int, input().split())

for i, key in enumerate([a, b, c]):
   if not isinstance(key, (int, float)):
       raise TypeError(
           f'The type of {i   1} element is incorrect')
foo(float(a), float(b), float(c))

In my code I have the next error: i can't write k8 into int variable.

1 k8 5
Traceback (most recent call last):
  File "C:\Users\User\PycharmProjects\digits\main.py", line 40, in <module>
    a, b, c = map(int, input().split())
ValueError: invalid literal for int() with base 10: 'k8'

How can I raise the TypeError when user input k8? And how to be in situation if user inputs k8 9 5h? I that case I need to Raise the TypeError with message The type of 1, 3 element is incorrect

CodePudding user response：

This ought to do it:

args = input().split()

f_args = []
errors = []
for i, arg in enumerate(args, 1):
    try:
        f_args.append(float(arg))
    except ValueError:
        errors.append(str(i))
if errors:
    raise TypeError(f"The type of {', '.join(errors)} element is incorrect")

foo(*f_args)