How do I query the dates in mongodb such that the entries with less than 1 hour difference is remove-CodePudding

MongoDB collection

I have this collection. I want to query entries so that either one of key "2" or "3" would be removed because the createdAt entries have a difference less than 1 hour. What would be the query?

CodePudding user response：

You can use $gt query. See the document here

And here is a code example. Just change the places with your property, which is createdAt in your scenario.

let user = await User.deleteMany({
    createdAt: { $gt: Date.now() - 3600000 } // 3600000 means 1 hour in millisecond
});

// Rest of your code

CodePudding user response：

Query

uses $dateTrunc with unit hour, that means keep the date as it is, but make zero all the left after the date
group by that trunc date => dates with same hour are in the same group
keep only one of them

*query doesn't work with difference, it works by same hour, for example 1:01 is the same with 1:59 but 1:59 is not same group with 2:01

Test code here

aggregate(
[{"$group":
  {"_id":{"$dateTrunc":{"date":"$createdAt", "unit":"hour"}},
   "doc":{"$first":"$$ROOT"}}},
 {"$replaceRoot":{"newRoot":"$doc"}}])