Regex: Replace last segment of url-CodePudding

I try to figure out the correct regex to replace the last segment of an url with a modified version of that very last segment. (I know that there are similar threads out there, but none seemed to help...)

Example:

https://www.test.com/one/two/three/mypost/
--->
one/two/three?id=mypost


https://www.test.com/one/mypost/
--->
one?id=mypost

Now I am stuck here: https://regex101.com/r/9GqYaU/1

I can get the last segment in capturing group 2 but how would I replace it? I think I will have to something like this:

  const url = 'https://www.test.com/one/two/three/mypost/'
  const regex = /(http[s]?:\/\/)([^\/] \/)*(?=\/$|$)/
  const path = url.replace(regex, `${myUrlWithoutTheLastSegmentAnd WithoutHTTPS}?id=$2`)
  return path

But I have no idea how to get the url without the last segment. I have currently only access to the whole string or group 1 (which is useless in this case) and then group 2, but not the string without group 2.

I would be very glad for any help here. Sometimes I just lack the knowledge of what is possible with regex and how to achieve it.

Thank you in advance.

Cheers

CodePudding user response：

You could use the URL class to extract the pathname and substring to remove the first '/'.

Then, you could put the last part of the pathname in a group and use it as a reference $1 for the replacement.

const url = new URL('https://www.test.com/one/two/three/mypost/').pathname.substring(1)

console.log(url.replace(/\/([^/]*)\/$/, '?id=$1'))