{
"lion":{
"age_in_years":"10",
"name":"king",
"country":"africa"
},
"elephant":{
"age_in_years":"15",
"name":"hero",
"country":"usa"
},
"racoon":{
"age_in_years":"5",
"name":"thanos",
"country":"syria"
},
}
This is the data I'm getting through a web socket in react-native. I want to sort it in ascending order based on the "age_in_years". So the oldest animal's data should be shown at top and the youngest data at the last.
CodePudding user response:
You sould better work with an array insted of object as below, first map it into array and parse the age_in_years
and sort it.
const obj2Array = Object.entries(<YourObject>).map(([key, value]) => ({...value, _id: key, age_in_years: parseInt(value.age_in_years)}));
const sorted = obj2Array.sort((a, b) => a.age_in_years - b.age_in_years);
Then you can use .reduce
if you wan the object, nevertheless you can use the sorted array to render it.
CodePudding user response:
Sort by age in years oldest first
// use slice() to copy the array
var byAge = array.slice(0);
byAge.sort(function(a,b) {
return a.age_in_years - b.age_in_years ;
});
CodePudding user response:
Store the values in array and make a sort function.
const numbers = [info.lion.age_in_years, info.elephant.age_in_years, info.racoon.age_in_years];
const ascNumbers = numbers.sort((a,b) => a-b);
If you need descending make it like this:
const descNumbers = numbers.sort((a,b) => b-a);