echo "Hello World";
string="v13.2.exe"
pattern='^v[0-9]*\.[0-9]*\.exe$'
if [[ $str =~ pattern ]]; then
echo "found"
else
echo "not found"
fi
it always print not found. what is wrong
CodePudding user response:
In one case ($str
) you are not using the variable you have defined ($string
). In the other (pattern
), you're missing the $
sign ($pattern
). Try
string="v13.2.exe"
pattern='^v[0-9]*\.[0-9]*\.exe$'
if [[ $string =~ $pattern ]]; then
echo "found"
else
echo "not found"
fi
found