My array look like this:
var theset=[
{
"set": "1",
"data": [
{ "field": "A", "value": "111", "check": true },
{ "field": "B", "value": "111", "check": false },
{ "field": "C", "value": "111", "check": true }
]
},
{
"set": "2",
"data": [
{ "field": "A", "value": "111", "check": true },
{ "field": "B", "value": "222", "check": false },
{ "field": "C", "value": "222", "check": true }
]
},
{
"set": "3",
"data": [
{ "field": "A", "value": "333", "check": true },
{ "field": "B", "value": "333", "check": false },
{ "field": "C", "value": "222", "check": true }
]
},
{
"set": "4",
"data": [
{ "field": "A", "value": "444", "check": true },
{ "field": "B", "value": "333", "check": false },
{ "field": "C", "value": "444", "check": true }
]
}
];
What I want to do is validate the "value" with other set on the same field only when the "check" is true.
The result is to return a true if there is a duplication of "value" in the set. The example will return a true because
- set 1: having duplicate value for field A with set 2
- set 2: having duplicate value for field A with set 1, duplicate value for field C with set 3
- set 3: having duplicate value for field C with set 2
- set 4: not consider as duplicate, even though the value of field B match with set 3 because of the check is false
so far I tried to do for loop on the list but this will have a lot of nested loop which is not efficient.
for(var i=0; i<theset.length; i ){
var checking = theset[i].data;
for(var j=0; j<checking.length; j ){
if(checking[j].check){
for(var k=0; k<theset.length; k ){
if(k!=i){
var checking2 = theset[k].data;
for(var l=0; l<checking2.length; l ){
...
}
}
}
}
}
}
Can anybody help me?
CodePudding user response:
one way can be for each set to filter the duplicate data with array.filter
then if there is duplicate do the wanted treatment
var theset = [
{
"set": "1",
"data": [
{ "field": "A", "value": "111", "check": true },
{ "field": "B", "value": "111", "check": false },
{ "field": "C", "value": "111", "check": true }
]
},
{
"set": "2",
"data": [
{ "field": "A", "value": "111", "check": true },
{ "field": "B", "value": "222", "check": false },
{ "field": "C", "value": "222", "check": true }
]
},
{
"set": "3",
"data": [
{ "field": "A", "value": "333", "check": true },
{ "field": "B", "value": "333", "check": false },
{ "field": "C", "value": "222", "check": true }
]
},
{
"set": "4",
"data": [
{ "field": "A", "value": "444", "check": true },
{ "field": "B", "value": "333", "check": false },
{ "field": "C", "value": "444", "check": true }
]
}
];
theset.forEach(set => {
var duplicate = set.data.filter(data => {
return theset.some(oneSet => oneSet.data.some(oneData => oneData.value === data.value));
});
if (duplicate.length) {
console.log(`the following set have duplicate ${set.set}`);
console.log(duplicate);
//treat as you want the set and the duplicate
}
});
CodePudding user response:
i would do it with a hash map
const theset = [
{
"set": "1",
"data": [
{ "field": "A", "value": "111", "check": true },
{ "field": "B", "value": "111", "check": false },
{ "field": "C", "value": "111", "check": true }
]
},
{
"set": "2",
"data": [
{ "field": "A", "value": "111", "check": true },
{ "field": "B", "value": "222", "check": false },
{ "field": "C", "value": "222", "check": true }
]
},
{
"set": "3",
"data": [
{ "field": "A", "value": "333", "check": true },
{ "field": "B", "value": "333", "check": false },
{ "field": "C", "value": "222", "check": true }
]
},
{
"set": "4",
"data": [
{ "field": "A", "value": "444", "check": true },
{ "field": "B", "value": "333", "check": false },
{ "field": "C", "value": "444", "check": true }
]
}
];
const hashmap = {};
theset.forEach((item) => {
item.data.forEach((obj) => {
if (!obj.check) {
return;
}
const key = JSON.stringify(obj);
if (!hashmap[key]) {
hashmap[key] = [];
}
hashmap[key].push(item.set);
})
})
console.log('hashmap', hashmap)
as a result you would get the following output:
{
"obj1": ["1","2"],
"obj2": ["1"],
"obj3": ["2","3"],
"obj4": ["3"],
"obj5": ["4"],
"obj6": ["4"]
}
- obj1 is common for set 1 and set 2
- obj3 is common for set 2 and set 3
you have the all needed information for your conclusions
of course, you could use a custom hash function rather than JSON.stringify()