XML - How to find specific attributes-CodePudding

I'm looking to print ALL elements witch have these three specific attributes: 'name', 'top', 'left' from an XML file. So far i can do it manualy by firstly printing all tags:

for elm in root.findall("./"): print(elm.tag)

and then i can go throgh what it prints one by one for example like:

for elm in root.findall("./momentaryButton"): print(elm.attrib['name'],elm.attrib['top'],elm.attrib['left']) etc.

I have a problem in writing a program which will find all the lines containing the XML tag properties "name", "top" and "left" and will write value of this properties in console all at once. Is there a way to do it?

I'm pasting an XML file below:

CodePudding user response：

I believe you are looking for something like

for elm in root.findall(".//*"): 
    if 'left' and 'name' and 'top' in elm.attrib.keys():
        for k,v in  elm.attrib.items():
            print(k,":",v)
        print('------------')

The output should all the attributes and their values for those elements which have all the three specified attributes.

CodePudding user response：

An XPath to select the elements that have the attribute @name, or @top, or @left:

//*[@name or @top or @left]

Applied to your code:

for elm in root.findall("//*[@name or @top or @left]"): 
print(elm.attrib['name'], elm.attrib['top'], elm.attrib['left'])