So i have a string that contains snowflake columns and i want to split the string to each column, I’m trying to use Regex to do this as it split string won't work in this situation. The string pattern i have tried is

string pattern = @"([^\s]*\s[^\s]*),"

though this pattern splits after the second consecutive space. Im not sure how to split it just after the alias. I am also using .net core 3.1. Any help would be appreciated..

current snowflake datacolumn string:

string columns = "nvl(u.\"Country\",'#N/A') \"Country\",u.\"CreatedDate\" \"CreatedDate\",nvl(u.\"Email\",'#N/A') \"Email\",u.\"LastModifiedDate\" \"LastModifiedDate\",nvl(u.\"Name\",'#N/A') \"Name\"";

expected output:
nvl(u."Country",'#N/A') "Country"
u."CreatedDate" "CreatedDate"
nvl(u."Email",'#N/A') "Email"
u."LastModifiedDate" "LastModifiedDate"
nvl(u."Name",'#N/A') "Name"

CodePudding user response：

You can use

string[] result = Regex.Split(text, @"(?<=\s""\w ""),");

See the

Another idea is to extract the matches with

var result = Regex.Matches(text, @"\b(?:nvl\([^()]*\)|u\.""[^""]*"")\s ""[^""]*""")
    .Cast<Match>()
    .Select(x => x.Value);

See

Details:

• \b - word boundary
• (?:nvl\([^()]*\)|u\."[^"]*") - nvl(...) or u."..."
• \s - one or more whitespaces
• "[^"]*" - ", zero or more non-"s, and a ".

CodePudding user response：

You can use a capture group (group 1) and exclude the comma in the second part after matching the space. To match all parts, you can match either a comma or the end of the string at the end of the pattern.

This part [^\s]* can be written as \S*

(\S*\s[^\s,]*)(?:,|$)

• ( Capture group 1
  • \S*\s[^\s,]* Match optional non whitespace chars, match a whitespace char and match optional non whitespace chars except a comme
• ) Close group 1
• (?:,|$) Match either a comma or assert the end of the string

For example

string pattern = @"(\S*\s[^\s,]*)(?:,|$)";
string input = @"nvl(u.""Country"",'#N/A') ""Country"",u.""CreatedDate"" ""CreatedDate"",nvl(u.""Email"",'#N/A') ""Email"",u.""LastModifiedDate"" ""LastModifiedDate"",nvl(u.""Name"",'#N/A') ""Name""";

foreach (Match m in Regex.Matches(input, pattern))
{
    Console.WriteLine(m.Groups[1].Value);
}

Output

nvl(u."Country",'#N/A') "Country"
u."CreatedDate" "CreatedDate"
nvl(u."Email",'#N/A') "Email"
u."LastModifiedDate" "LastModifiedDate"
nvl(u."Name",'#N/A') "Name"

A bit more specific pattern using to match 1 or more characters and match word characters between double quotes:

 (\S \s"\w ")(?:,|$)

Regex demo