I am trying to create a route that takes either one of two parameters.
web.php :
Route::get('myroute/{a?}/{b?}', [MyController::class, 'testFunction'])->name('test.testFunction');
Controller:
public function testFunction( $a = null, $b = null) {
dd($a, $b);
// stuff
}
Ajax call
function test($b_id) {
$url = "{{ route('test.testFunction', ':b') }}";
$url = $url.replace(":b", $b_id);
$.ajax({
url: $url,
type: 'GET'
})}
However the dd returns me $b_id, null
instead of null, $b_id
.
How can I pass only b as parameter and omit a ?
CodePudding user response:
This is not really possible at the moment but there is a workaround.
You can pass the parameters in an named array and change the route to simply Route::get('myroute' ...)
:
route('test.testFunction', ['a' => 'xyz', 'b' => 'yzt'])
===== creates
http://myroute?a=xyz&b=yzt
Afterwards you can check if the parameters a
or b
are present and retrieve them normally if they are.