check if numeric element is in an interval key dictionary in python-CodePudding

from the following dictionary with tuple as keys and a string as value:

dict_interval = {(1,5):"foo",(5,100):"bar"}

by using the dict, how would be possible to use a function with the following behaviour?

age = 4    
categorizer(age, dict_interval)

gives the following output:

"foo"

CodePudding user response：

If you want all the values where the age is in the interval you can use the following code:

def get_all_values(age):
   res = []
   for key, value in dict_interval .items():
      if (age >= key[0] and age <= key[1]):
         res.append(value)
   return res

this function will return a list of all the correct values. If you can only get 1 correct value you can do it like that:

def get_value(age):
   for key in dict_interval .keys():
      if (age >= key[0] and age <= key[1]):
         return dict_interval[key]

CodePudding user response：

def categorizer(value, dict_interval):
    for k in dict_interval:
        if k[0] < value < k[1]:
            return(dict_interval[k])

This should work, assuming that key is unique I guess.