How can we generate a random N X N
binary matrix using Numpy, where:
- each value is either
0
or1
- every row sums up to
1
- every column sums up to
1
For example, a valid matrix might be
[[1 0 0]
[0 0 1]
[0 1 0]]
while an invalid one is
[[1 0 0]
[0 0 1]
[0 0 1]]
Tried doing the following, but failed to figure out how to shuffle the values in each column using a unique index.
N = 10
a = np.zeros((N,N))
a[0,:] = 1
CodePudding user response:
Create an n
by n
identity matrix, and then shuffle all of the rows. The identity matrix is a binary matrix where each row and column sums to one, and shuffling the rows preserves this property:
n = 5
result = np.identity(n)
np.random.shuffle(result)
print(result)
This will output something like:
[[0. 1. 0. 0. 0.]
[0. 0. 0. 0. 1.]
[0. 0. 0. 1. 0.]
[1. 0. 0. 0. 0.]
[0. 0. 1. 0. 0.]]
CodePudding user response:
Use np.random.permutation
to create random column indices and then use advanced indexing fill indices with 1s:
N = 10
a = np.zeros((N,N), dtype=int)
a[np.arange(N), np.random.permutation(N)] = 1
a
array([[0, 0, 0, 0, 0, 0, 1, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 1],
[0, 0, 0, 0, 0, 0, 0, 0, 1, 0],
[0, 1, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 1, 0, 0, 0, 0],
[0, 0, 0, 0, 1, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 1, 0, 0],
[1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 1, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 1, 0, 0, 0, 0, 0, 0]])