delete duplicates and sorts output-CodePudding

would anyone help me to solve this? I have this code, they need the calculations to sort from the largest to the largest (first numbers) and then to eliminate duplications i know i should use .sort () but I'm clueless who I do

for these results

5=1=1
5=1=1
1=1=5
1=5=1
1=1=5
1=5=1
4=2=1
4=1=2
2=1=4
2=4=1
1=2=4
1=4=2
3=3=1
3=1=3
3=1=3
3=3=1
1=3=3
1=3=3
3=2=2
3=2=2
2=2=3
2=3=2
2=2=3
2=3=2

output inline thos I want this to do

1=1=5
1=2=4
1=3=3
1=4=2
1=5=1
2=1=4
2=2=3
2=3=2
2=4=1
3=1=3
3=2=2
3=3=1
4=1=2
4=2=1
5=1=1

code

def part(n, k):
    def _part(n, k, pre):
        if n <= 0:
            return []
        if k == 1:
            if n <= pre:
                return [[n]]
            return []
        ret = []
        for i in range(min(pre, n), 0, -1):
            ret  = [[i]   sub for sub in _part(n-i, k-1, i)]
        return ret
    return _part(n, k, n)
x = part(7,3)
for i in x:
   print(str(i[0]) '=' str(i[1]) '=' str(i[2]))
   print(str(i[0]) '=' str(i[2]) '=' str(i[1]))
   print(str(i[1]) '=' str(i[2]) '=' str(i[0]))
   print(str(i[1]) '=' str(i[0]) '=' str(i[2]))
   print(str(i[2]) '=' str(i[1]) '=' str(i[0]))
   print(str(i[2]) '=' str(i[0]) '=' str(i[1]))

CodePudding user response：

The standard list sorting will work on this.
To remove dupes, convert to set and back to list.

EDIT
So, slight editing of your last for loop. For readability I advise to use a so-called f-string.
I misunderstood your question due to the original code formatting, but this short example should work on the result of your function...

lst = []
for elem in x:
   lst.append(f"{elem[0]}={elem[1]}={elem[2]}")
   lst.append(f"{elem[0]}={elem[2]}={elem[1]}")
   lst.append(f"{elem[1]}={elem[0]}={elem[2]}")
   lst.append(f"{elem[1]}={elem[2]}={elem[0]}")
   lst.append(f"{elem[2]}={elem[0]}={elem[1]}")
   lst.append(f"{elem[2]}={elem[1]}={elem[0]}")

lst = sorted(list(set(lst)))
for elem in lst:
    print(elem)

output

1=1=5
1=2=4
1=3=3
1=4=2
1=5=1
2=1=4
2=2=3
2=3=2
2=4=1
3=1=3
3=2=2
3=3=1
4=1=2
4=2=1
5=1=1

CodePudding user response：

You can use a set

set_data_str = """5=1=1
5=1=1
1=1=5
1=5=1
1=1=5
1=5=1
4=2=1
4=1=2
2=1=4
2=4=1
1=2=4
1=4=2
3=3=1
3=1=3
3=1=3
3=3=1
1=3=3
1=3=3
3=2=2
3=2=2
2=2=3
2=3=2
2=2=3
2=3=2"""

# break the string into a list on the new lines
# create a set from the list
set_data = set(set_data_str.split('\n'))

# sort the set into a list
sorted_set_data = sorted(set_data)

# convert the sorted list into a string to print it
print('\n'.join(sorted_set_data))

Credit to @Edo-Akse for better formatting