I have to remove all the objects from array that contain the same id present in another array.

This code works

myArray = [{id: 1, value: 'a'}, {id: 2, value: 'b'}, {id: 3, value: 'c'}];
itemsToRemove = [{id: 2, value: 'x'}, {id: 3, value: 'y'}];
for (const item of itemsToRemove) {
    myArray.splice(myArray.findIndex(a => a.id === item.id), 1);
}

but I'm looking for a more elegant way to do it. I've tried also

const newArray = myArray.filter(a => itemsToRemove.findIndex(i => i.id === a.id));

but doesn't works. (it creates a new array, but at least one item with the same id remains in the new array).

Is there a clean and concise way to do it?

CodePudding user response：

You're close, but as