How can I form a pretty JSON from a string with backslashes?-CodePudding

I have a Gin-Gonic REST API in Golang. Here I am trying to output users that are already registered as JSON, currently in Postman I only get that:

(You can ignore the lastRequest-Attribut, because it is currently always nil)

"[{\"id\":\"e61b3ff8-6cdf-4b23-97a5-a28107c57543\",\"firstname\":\"John\",\"lastname\":\"Doe\",\"email\":\"[email protected]\",\"username\":\"johndoe\",\"token\":\"19b33c79-32cc-4063-9381-f2b64161ad8a\",\"lastRequest\":null},

But I want it like this:

[{
        "id": "e61b3ff8-6cdf-4b23-97a5-a28107c57543",
        "username": "johndoe",
        "email": "[email protected]",
        "token": "19b33c79-32cc-4063-9381-f2b64161ad8a",
        "lastRequest": null
    }]

How do I manage this, I tried many things with the 'json.MarshalIndent' (from this stackoverflow-post), however it didn't change anything for me, what do I need to do? Because the backslashes stay no matter what I do, at most \t or spaces are inserted. I have also read that I have to do it as a byte array, but that didn't work for me either (maybe I did something wrong here too).

Here my current code:


var users []User
r.GET("/getusers", func(c *gin.Context) {
    usersArr := make([]User, len(users))
    for i := 0; i < len(users); i   {
        usersArr[i] = users[i]
    }
        
    userJson, err := json.Marshal(testUser)
    if err != nil {
        c.JSON(400, gin.H{"error": err.Error()})
    } else {
        c.JSON(200, string(userJson))
    }
})

type User struct {
    Id          string        `json:"id"`
    Firstname   string        `json:"firstname"`
    Lastname    string        `json:"lastname"`
    Email       string        `json:"email"`
    Username    string        `json:"username"`
    Token       string        `json:"token"`
    LastRequest []lastRequest `json:"lastRequest"`
}

CodePudding user response：

Two things:

The "backslashes" are just escape characters. They aren't literally there.
Indenting JSON is a simple matter of calling the appropriate Indent function:

If you have the JSON string already, use the json.Indent function from the encoding/json package:

input := []byte("[{\"id\":\"e61b3ff8-6cdf-4b23-97a5-a28107c57543\",\"firstname\":\"John\",\"lastname\":\"Doe\",\"email\":\"[email protected]\",\"username\":\"johndoe\",\"token\":\"19b33c79-32cc-4063-9381-f2b64161ad8a\",\"lastRequest\":null}]")
buf := &bytes.Buffer{}
if err := json.Indent(buf, input, "", "\t"); err != nil {
    panic(err)
}
fmt.Println(buf.String())

Playground link

However, if you're trying to marshal directly into the indented form, just use the MarshalIndent function intead of Marshal:

    userJson, err := json.MarshalIndent(testUser, "", "\t")

CodePudding user response：

Well this would be my first answer in stackoverflow, hope this helps.

Go gin framework comes with a few handy functions, since I've got no idea what version of golang nor Gin Framework you're using you could try this:

var users []User
r.GET("/getusers", func(c *gin.Context) {
    usersArr := make([]User, len(users))
    for i := 0; i < len(users); i   {
        usersArr[i] = users[i]
    }
        
    if err != nil {
        c.JSON(400, gin.H{"error": err.Error()})
    } else {
        c.JSON(200, users)
// If Indentation is required you could try:
        c.IndentedJSON(200, users)
    }
})

type User struct {
    Id          string        `json:"id"`
    Firstname   string        `json:"firstname"`
    Lastname    string        `json:"lastname"`
    Email       string        `json:"email"`
    Username    string        `json:"username"`
    Token       string        `json:"token"`
    LastRequest []lastRequest `json:"lastRequest"`
}