I have a json file named "input.json":

{
  "item1": "banana",
  "item2": false
}

and I have a bash command that takes in a json input, which then takes in the hash of the above file content as the value for the "input" key:

executable '{"input": {"item1": "banana", "item2": false}, "option1": "value1", "option2": "value2" }'

How can I pass the json content from input.json file into the command? I have tried:

• create the one-line json hash from the input.json with jq -c . input.json and pass the hash to a variable, then reference that variable in the command - it did not work (value expected is missing - likely because of the single quote that messed up the reference).

Any help or pointer is appreciated.

CodePudding user response：

You can follow the steps as you had indicated, which should work. Create the base64 content, store it in a variable and pass it to jq

#!/usr/bin/env bash
# Bash script to construct a base64 of a JSON content and passing
# it to an another command

# Create the base64
base=$(jq -c . input.json | base64)

# Create the JSON that stores the above hash
json=$(jq -cn --arg b64 "$base" '{"input": $b64, "option1": "value1", "option2": "value2" }')

# If you want the JSON to be a literal string, use the '@text' filter
# with 'jq'
jsonString=$(jq -cn --arg b64 "$base" '{"input": $b64, "option1": "value1", "option2": "value2" } | @text')

# Pass the contents of either 'json' or 'jsonString', depending on 
# how your executable parses the command line argument