I can't seem to figure out why the values of the first column after the 3 are being reset to 1 and then 1 again. I think it has to do with the not 999 if statement, but I'm not sure what to add or change. Any help is appreciated thank you!
n = 15 #the number the matrices will be an n*n of
a = [[ 0 for x in range(n)] for x in range(n)]
a[-1][-1] =111
a[0][3] =999
def Manhattan(x):
k = 1
m = 1
for i in range(n):
for j in range(n):
if (x[i][j] < 1):
if (x[j][i] < 1):
if (x[i][j-1] != 999 or x[j-1][i] !=999 ):
k = x[i][j-1]
x[i][j] = k 1
m = x[j-1][i]
x[j][i] = m 1
else:
k = x[i][j]
x[i][j] = k 1
for row in x:
print()
for val in row:
print('M' %val, end = " ")
Manhattan(a)
CodePudding user response：
im not completely sure what your program is meant to do but i think this is what youre trying to achieve as output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
7 8 9 10 11 12 13 14 15 16 17 18 19 20 21
8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
9 10 11 12 13 14 15 16 17 18 19 20 21 22 23
10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
15 16 17 18 19 20 21 22 23 24 25 26 27 28 29
code:
n = 15 #the number the matrices will be an n*n of
a = [[ 0 for x in range(n)] for x in range(n)]
a[-1][-1] = 111
a[0][3] = 999
def Manhattan(x1):
start_value = 0
for x in range(n):
start_value = 1
second_val = start_value
for y in range(n):
x1[y][x] = second_val
second_val = 1
for line in x1:
for char in line:
print('M' %char, end = " ")
print()
Manhattan(a)
your code is fairly unorganized it makes it hard to understand but if this was your goal then what you need to do is increment a value starting from 1 by 1 each outer loop while looping through the matrix and then every iteration of the inner loop you increase it by 1 and set the value into the corresponding index.
CodePudding user response：
I think your question is why x[0][3] equals 1 after calling the function Manhattan, well that because your else statement is compare with if (x[j][i] < 1) statement.
So, when the code go on x[3][0], the if (x[0][3]) will equal False, then go to the else statement, that means: k=x[3][0]=0, and then x[3][0]=0 1=1.
I'm not sure if this output is your expectation:
1 2 3 1003 1004 1005 1006 1007 1008 1009 1010 1011 1012 1013 1014
2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
7 8 9 10 11 12 13 14 15 16 17 18 19 20 21
8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
9 10 11 12 13 14 15 16 17 18 19 20 21 22 23
10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
15 16 17 18 19 20 21 22 23 24 25 26 27 28 111
Code:
def Manhattan(x):
for i in range(n):
for j in range(n):
if x[i][j] == 111:
break
up = 0
left = 0
if x[i-1][j] > 0 and bool(i):
up = x[i-1][j]
if x[i][j-1] > 0 and bool(j):
left = x[i][j-1]
if bool(up) and bool(left):
x[i][j] = x[i][j] min(up, left) 1
elif bool(up):
x[i][j] = x[i][j] up 1
elif bool(left):
x[i][j] = x[i][j] left 1
else:
x[i][j] = x[i][j] 1
for row in x:
print()
for val in row:
print('M' %val, end = " ")