Here is the bash function to parse a json file use 'jq' command:
jq_fullpath_endkey() {
PATHARRAY=$(jq -c 'paths | select(.[-1] == "'$keyword'")|map(strings |= ".\(.)" | numbers |= "[\(.)]") | join("")' **${news.json}**)
}
The news.json
is the json file that contains all the content I'd like to parse with jq.
The function works once I replace ${news.json}
with a variable named response
which contains news.json
content as string.
Below is the command which works:
PATHARRAY=$(jq -c 'paths | select(.[-1] == "'$keyword'")|map(strings |= ".\(.)" | numbers |= "[\(.)]") | join("")'**<<< "$response"**)
My question is how can I use 'json file' as part of the jq cmd ? I suspect there is something wrong with double/single quote I am using.
CodePudding user response:
I figure it out with "parameter substitution" in bash
myfile="news.json"
PATHARRAY=$(jq -c 'paths | select(.[-1] == "'$keyword'")|map(strings |= ".\(.)" | numbers |= "[\(.)]") | join("")' ${myfile})
Related concepts: variable substitution command substitution