My Visual Studio Code shows "undefined method". I want to know is it possible to "fix" it with some VSC settings or maybe there is a PHP solution. I have this
class A
{
public function someMethodA()
{
// ...
}
}
class B extends A implements Bint
{
public function someMethodB()
{
// ...
}
}
interface BInt
{
public function someMethodB();
}
class C
{
public function someMethodC(Bint $b)
{
// VSC shows indefined method
return $b->someMethodA();
}
}
My interface doesn't have someMethodA
, is it possible to "inherit" it from Class A
to get rid of "error"? This class comes from a package, it has no interface and I need to extend it
getStatusCode()
exists, it is public, everything works, but Visual Studio Code cannot understand it
CodePudding user response:
Focussing on your code example, not your screenshot, your IDE is correct, and you should listen to what it's telling you.
The contract of method someMethodC
is that it can accept any implementation of interface Bint
. That guarantees that you can call someMethodB
, but does not guarantee anything else.
If the method is passed an instance of class A, then PHP will allow you to call someMethodA
on it, but it might be passed some other object, such as:
class OnlyB implements Bint {
public function someMethodB() {
// ..
}
}
The contract (signature) of someMethodC says you can pass this object, but when you call someMethodA
, you will get an error.
If you want the method to always receive instances of class A, say so in the signature:
public function someMethodC(A $b) {
return $b->someMethodA();
}
If you want it to accept any implementation of Bint
, then you should only call methods guaranteed to exist by that interface.