Why am i getting False in this boolean question-CodePudding

A= True

B= True

y = not(A or B) == (not(A)) and (not(B))

print (y)

gives output as False on python.

Should it not be true (False==False)?

CodePudding user response：

you need to pay attention to order of operations in general, it is always prefferred to use paranthesis when it is ambigous in your case, it is translated as

A = True
B = True
y = (not(A or B) == (not(A))) and (not(B))

which if we follow carefully is:

y = (not(True or True) == (not(True))) and (not(True))
y = (not(True) == (False)) and (False)
y = (False == False) and (False)
y = True and False
y = False

hope this helps, and good luck on your journey

CodePudding user response：

this what you need to do to get what you wanted : y = not(A or B) == ( not(A) and not(B) )

in what you did you got not(A or B) == (not(A)) as true and after this you have true and (not(B)) and this false!