FileCount on Unix-CodePudding

I am trying to find the number of files in a directory. I am using the ls command. Based on the Number of Files, I need to display the count and a message. Script doesn't provide the desired output. Any assistance will be appreciated.

#!/bin/sh

FILECOUNT = $(ls /opt/report/ | grep *.ZIP_30 | wc -l);

if [ $FILECOUNT -gt "0" ]; then
      echo "Statistic.filecount: $FILECOUNT";
      echo "Message.filecount: Normal";
else
      echo "Statistic.filecount: $FILECOUNT";
      echo "Message.filecount: Warning";
fi;

exit 0;

CodePudding user response：

It's a general advise not to parse the result of ls, therefore I would advise you the following command:

find /opt/report/ -maxdepth 1 -name "*.ZIP_30" | wc -l

CodePudding user response：

You have a syntax error.

No spaces allowed around = in shell, so:

filecount=$(grep -c ZIP_30 /opt/report/*)