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Output number of non-consecutive failures from historical data in Bigquery

Time:05-24

this is related to my previous scenario.

I have a dataset like this:

WITH failure_table AS
  (SELECT 'Andrea' AS name, 'Failure' AS status, '2022-04-28 4:00:00' AS timestamp
   UNION ALL SELECT 'Karl', 'Failure', '2022-04-28 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-04-27 4:00:00'
   UNION ALL SELECT 'Karl', 'Failure', '2022-04-27 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-04-26 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-04-25 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-03-30 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-03-29 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-03-28 4:00:00'
   UNION ALL SELECT 'Karl', 'Failure', '2022-03-28 4:00:00')
   UNION ALL SELECT 'Andrea', 'Failure', '2022-03-15 4:00:00')

Aside from outputting the timestamp in which a user first committed a failure, and consecutively commits a failure status every day, leading up to today (2022-04-29), I also want to output the non-consecutive block of days in which Karl or Andrea commits a failure.

In this case, Andrea started failing recently at 2022-04-25 4:00:00 and commits 3 failure blocks (03-15, 03-28 to 03-30, 04-25 to 04-28) while Karl started failing recently at 2022-04-27 4:00:00 and commits 2 failure blocks (03-28, 04-27 to 04-28).

Final output should be

name status started recently failing timestamp recent days failing total days failing total failure blocks
Andrea Failure 2022-04-25 4:00:00 4 8 3
Karl Failure 2022-04-27 4:00:00 2 3 2

Thank you for those who can help, I really would appreciate it.

CodePudding user response:

Take a look at below query although it's not refined yet. Hoping help you find some clue to approach your problem.

  1. failure_blocks is for figuring out each consecutive failing days.
  2. last_blocks is for finding last failing block to identify started_recently_failing_timestamp
  3. Main query generates the expected output from previous CTEs.
WITH failure_table AS (
  SELECT 'Andrea' AS name, 'Failure' AS status, TIMESTAMP '2022-04-28 4:00:00' AS dt
   UNION ALL SELECT 'Karl', 'Failure', '2022-04-28 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-04-27 4:00:00'
   UNION ALL SELECT 'Karl', 'Failure', '2022-04-27 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-04-26 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-04-25 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-03-30 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-03-29 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-03-28 4:00:00'
   UNION ALL SELECT 'Karl', 'Failure', '2022-03-28 4:00:00'
   UNION ALL SELECT 'Andrea', 'Failure', '2022-03-15 4:00:00'
),
failure_blocks AS (
  SELECT *,
         COUNTIF(diff <> 1) OVER (PARTITION BY name) AS total_failure_blocks,
         COUNT(*) OVER (PARTITION BY name) AS total_days_failing,
         SUM(diff - 1) OVER (PARTITION BY name ORDER BY dt) AS block,
    FROM (
      SELECT name, status, dt, IFNULL(DATE_DIFF(dt, LAG(dt) OVER (PARTITION BY name ORDER BY dt), DAY), 0) AS diff
        FROM failure_table
    )
),
last_blocks AS (
SELECT * EXCEPT(diff, block), 
       COUNT(*) OVER (PARTITION BY name, block) AS recent_days_failing,
       FIRST_VALUE(dt) OVER (PARTITION BY name, block ORDER BY dt) AS block_start_dt
  FROM failure_blocks
)
SELECT name, status, 
       MAX(block_start_dt) OVER (PARTITION BY name) AS started_recently_failing_timestamp,
       recent_days_failing,
       total_days_failing,
       total_failure_blocks,
  FROM last_blocks 
 WHERE TRUE QUALIFY dt = started_recently_failing_timestamp
;

enter image description here

CodePudding user response:

Consider also below approach

select name, status,
  sum(if(rank = 1, consecutive_days, 0)) as recent_days_failing,
  sum(consecutive_days) as total_days_failing,
  count(block_id) as total_failure_block_ids
from (
  select name, status, block_id, 
    date_diff(max(dt), min(dt), day)   1 as consecutive_days,
    rank() over(partition by name, status order by block_id) rank
  from (
    select name, status, date(timestamp) dt,
      row_number() over(partition by name, status order by timestamp)   
      date_diff(current_date, date(timestamp), day) as block_id
    from failure_table
  )
  group by name, status, block_id
)
group by name, status   

if applied to sample data in your question - output is

enter image description here

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